Question

a ball is thrown vertically upward with a speed 40m/s. what height it will rise. what time it will take to reach the thrower hand, if v=10m/s. represent the whole situation graphically.​

Answer 1

Answer:

According to the equation of the motion under gravity

v

2

−u

2

=2gs

u=initial velocity of the stone=40m/s

v= Final velocity of the stone=0m/s

Let h be the maximum height attained by the ball

Therefore,

0

2

−40

2

=2(−10)h

h=(40×40)/20=80

Therefore, total distance covered by the ball during its upward and downward journey=80+80=160m

Net displacement during its upward and downward journey=80+(−80)=0

Explanation:

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