Question

A Ball is thrown vertically upward with a speed of 19.6 m/s from the top of a tower it return to the earth in 6 sec find the height of tower​

Answer 1

Answer:

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Answer 2

Speed of Ball: 19.6m/s

Time Taken: 6sec

V= 0

U= 19.6

S=?

T= 6sec

By Applying 2rd Equation of Motion

From equation of motion

 s=ut+21​at2

s=19.6×6−21​×3.26×36

s=58.9

s=59m

Hence, the height of the tower is 59 m

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