Question

A ball is thrown vertically upward with a velocity 39.2m/s. Find the velocity and height of the ball after 2s.​

Answer 1

Might Help! Thanks!

$\mu = 39.2m/s\\\\a = -9.8 m/s^{2}\\\\v = \mu + at\\\\v = 39.2 - 9.8(2)\\\\v = 39.2 - 19.6\\\\v = 19.6m/s\\\\s = \mu t + \frac{1}{2}at^{2}\\\\s = 39.2(2) - \frac{1}{2}9.8(2)^{2}\\\\s = 78.4 - 19.6\\\\s = 58.8m$