Question

A ball is thrown vertically upward with a velocity of 10 metre per second IT return to the ground with a velocity of mine metre per second if g is equal to 9.8 metre per second then the maximum height attained by the ball is nearly. ​

Answer 1

Answer:

initial velocity (u) =10

final velocity (v) =-9 (coming downwards)

gravity acceleration =-9.8 (coming downwards)

by applying equation s= ut+1/2at2

we get s=10t+1/2×-9.8t2

now we are finding t by equation v=u+at

-9=10-9.8t

19/9.8=t

t=2(approximately)

now putting t=2 in equation above we get

s=10×2-1/2×9.8×4

s=20-19.6

.4