Question

A ball is thrown vertically upward with a velocity of 10 m/s. Calculate the height attained by the Ball and time taken by it to reach the highest point if the acceleration of the ball is -10 m/s2 during its motion.​

Answer 1

Displacement = 2×2

= 4 m

since no force acting upward Acceleration along north =20/10

= 2m/s

Displacement along north= 1/2×(2×2×2)

=4m

Resultant displacement=(4^2+4^2)^1/2.

= 4×(2)^1/2 m

Answer 2

Answer:

s = 5 m

Explanation:

u=10 m /s

a=-10m/s2

v=0m/s

s=?

now,

v2=u2+2as

(0)2=(10)2+2×(-10)×s

-100= -20s

-100/-20=s

s=5 m