Question

a ball is thrown vertically upward with a velocity of 14m/s calculate the maximum height which it rises

​

Answer 1

Answer:

122.5

Explanation:

Initial velocity (u) = 49 m/s Final velocity (v) = 0 m/s

Gravity in toward down = + 9.8 m/s2 Gravity in toward up = - 9.8 m/s2

(i) We know, V2 - u2 = 2gs

or, (o)2- (49)2 = 2 X 9.8 X S

or, s = - (49)2/ 2 X 9.8 = 122.5 m

Maximum height = 122.5 m

(ii) We know, v = u + gt

or 0 = 49 +(- 9.8) X t

or 9.8 X t = 49

or, t = 49/ 9.8 = 5 s

If, time for upward direction = time for downward direction

Then, total time taken by a ball to return back = 5 + 5 = 10 s

i hope this helps you.

please Mark me as brainliest