A ball is thrown vertically upward with a velocity of 20 m/s from a top of tower having a height of 50m.what time elapsed when it again passess the edge of the tower
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Explanation:
given
u = 20m/s
h = 50m
g = 10m/s
v = 0m/s
v= u+hy
0= 20+ 10t
10t= 20
t=2sec
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