Accountancy, asked by Anonymous, 11 months ago

a ball is thrown vertically upward with a velocity of 20m/s . calculate the maximum height attain by the ball ?

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Answered by Anonymous

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Maximum height attained by the ball is which is vertically thrown up➡

Height:-

$u {}^{2} \div 2g$

$20 {}^{2} \div 2 \times 10$

H=400/20

H= 20 m.

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Answered by Anonymous

SOLUTION

u= 20m/s

v= 0

Height= s= ?

So,

=v^2= u^2+2gs. {here a=g due to gravity}

=) 0^2=(20)^2+2×9.8×s

=) s×2×9.8= -400

=) s= -400×10/2×9.8

=) s= -1000/49

=) s= 20.41 (Approx)

Distance is never negative so,

maximum height= 20.41 (approx)

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yeshkashyap: hy

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a ball is thrown vertically upward with a velocity of 20m/s . calculate the maximum height attain by the ball ?

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