A ball is thrown vertically upward with a velocity of 20m/s calculate the maximum height reached by the ball
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Answered by
14
If air resistance is neglected, just use the equation below:
height = (vf^2 - vi^2)/2g
where:
vf - final velocity(at the maximum height it will be zero)
vi = initial velocity (20m/s)
g - acceleration due to gravity (-9.8m/s^2
height = [(0m/s)^2 - (20m/s)^2] / 2(-9.8m/s^2)
height = 20 meters
Answered by
18
u=20
g=10
v=0
h=?
by using third equation of motion
v²=u²+2as
u²=2gh
400=20h
h=20
hope it helps
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