a ball is thrown vertically upward with a velocity of 39.2m/s. find its maximum height
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Answer: v=0 m/s
u= 39.2 m/s
g= -9.8 m/s²
v²-u²=2gs
0²-39.2²= 2 x -9.8 x s
-1536.64= -19.6 x s
s= 1536.64/19.6( mins signs cancelled)
s= 78.4 m
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