Question

a ball is thrown vertically upward with a velocity of 40m/s (take g= 10m/s^2) Calculate a) the height reached by the ball b) the time taken by the ball to reach the height​

Answer 1

Answer:

a) 80m, b) 4sec

Step-by-step explanation:

given,

v=40m/s

g=10m/s^2

(a) v=(2gh)^1/2

h=v^2/2g

h=40^2/2×10

h=80m

(b) t=(2h/g)^1/2

t=(2×80/10)^1/2

t=4sec

Answer 2

Here,

g = - 10 m/s² (Upward)

We know,

2gh = v² - u²

→ h = (- u²)/(2g)

→ h = (- 40 m/s × - 40 m/s)/(2 × 10 m/s²)

→ h = 80 m

& v = u + gt

→ t = (v - u)/a

→ t = - u/a

→ t = - (40 m/s)/(- 10 m/s²)

→ t = 4 s