A ball is thrown vertically upward with a velocity of 49m/s calculate maximum height it reaches (take acceleration on due to gravity =9.8m/s2)?
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your answer is 122.5meters height.
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H = u² / (2g)
= (49 m/s)² / (2 × 9.8 m/s²)
= 122.5 m
Maximum height it reaches is 122.5 m
= (49 m/s)² / (2 × 9.8 m/s²)
= 122.5 m
Maximum height it reaches is 122.5 m
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