Question

a ball is thrown vertically upward with a velocity of 98m/s and after 10 seconds it reach the maximum height . the average acceleration of the ball is​

Answer 1

Answer:

Given,

Initial Velocity = 98m/s

Final velocity = 0

Time taken = 10 seconds

We know that,

$acceleration = \frac{v - u}{t}$

Therefore,

$acceleration = \frac{0 - 98}{10} = \frac{98}{10} =9.8$

Therefore the acceleration is 9.8 m/s²