Question

a ball is thrown vertically upward with a velocity of 98m/s if it takes 10sec to reach the highest point then its accelearation ?

Answer 1

$accelation = \frac{v - u}{t}$

thrown with a velocity=9.8m/s....initcial velocity

final velocity is 0m/s becuase the stone stop for few seconds at the end of the trip.....then

$\large{timetaken=10sec}$

$accelaration = \frac{0mpersec - 98mpersec}{10sec} \\ = - 9.8mpersecond {}^{2}$