Question

A ball is thrown vertically upward with an initial velocity of 80 m/s. Find the height of the ball at time = 10s. (take g=10m/s^2)
(a)300m
(b)800m
(c)10000m
(d)500m​

Answer 1

Answer:

According to my opinion, answer should be 1300 m. Hope it helps you. The given Option (1) may have typing error, it should be 1300 m instead of 300 m.

Explanation:

h = ut + 1/2gt^(2)

h = (80)(10) + 1/2(10)(10)^(2)

h = 800 + 500

h = 1300 m ---> Answer

Answer 2

HEIGHT MEANS S

SO LET'S APPLY 2ND EQUATION OF MOTION

G=10

$s=ut+\frac{1}{2} at^2$

$s=80*10+\frac{1}{2} 10*10^2\\s=800+500\\s=1300-metres$

since option is not matching ,but i think the answer is 1300 metres

u can also see answer on go.ogle