Question

A ball is thrown vertically upward with an initial velocity of 49m/s find the position of the ball after 7sec. of the throw?

Answer 1

u = 49 m/s
v=0
t=7sec
a= v-u/t
= 0-49/7 = -49/7 = -7m/s2
s = ut + 1/2 at2
= 49×7 + 1/2 × -7 × 7∆2
= 171.5 metres

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