Question

A ball is thrown vertically upward with initial speed 40 m/s. The distance travelled by the ball in last second of upward journey is (g = 10 m/s2)​

Answer 1

Answer:

Initial Velocity u=40

Fianl velocity v=0

Height, s=?

By third equation of motion

v

2

−u

2

=2gs

0−40

2

=−2×10×s

s=

20

160

⇒s=80m/s

Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m

Total Diaplacement =0, Since the initial and final point is same.

Explanation:

this is the answer please mark as brainliest

Answer 2

Explanation:

given ,

u= 40 m/s

v = 0 m/s

g = 10 m/s²

v² = u² + 2aS

0² = 40² +2*(-g)×S

0 = 1600 + (-20)×S

20S = 1600

S = 80m

g is negative because the object is moving upwards but g is acting down wards