Physics, asked by ayushdey19, 4 months ago

a ball is thrown vertically upward with initial velocity 75m/s. The distance covered by it in 8th secondof its motion is------(g=10m/s^2)​

Answers

Answered by anjaliqueen3108
1

Answer:

Answer:final velocity=?

Answer:final velocity=?u= 75 m/ s

Answer:final velocity=?u= 75 m/ st= 8 sec

Answer:final velocity=?u= 75 m/ st= 8 secg= 10 m/s²

Answer:final velocity=?u= 75 m/ st= 8 secg= 10 m/s²v= u+ gt

Answer:final velocity=?u= 75 m/ st= 8 secg= 10 m/s²v= u+ gt = 75+10×8

Answer:final velocity=?u= 75 m/ st= 8 secg= 10 m/s²v= u+ gt = 75+10×8 = 75+80

Answer:final velocity=?u= 75 m/ st= 8 secg= 10 m/s²v= u+ gt = 75+10×8 = 75+80 = 155m/s

Answer:final velocity=?u= 75 m/ st= 8 secg= 10 m/s²v= u+ gt = 75+10×8 = 75+80 = 155m/ss=?

Answer:final velocity=?u= 75 m/ st= 8 secg= 10 m/s²v= u+ gt = 75+10×8 = 75+80 = 155m/ss=?s= ut+1/2 at²

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