Question

A ball is thrown vertically upward with speed v from the top of a tower and it reaches the ground with speed 4v. What is height of tower?

Answer 1

Explanation:

Let the height of the tower be h.

Let the height of the tower be h.Initial velocity (u) = v m/s

Let the height of the tower be h.Initial velocity (u) = v m/sFinal velocity (v) = -3v m/s

Let the height of the tower be h.Initial velocity (u) = v m/sFinal velocity (v) = -3v m/sUsing Newton's third equation of motion :

Let the height of the tower be h.Initial velocity (u) = v m/sFinal velocity (v) = -3v m/sUsing Newton's third equation of motion :v² - u² =2as

Let the height of the tower be h.Initial velocity (u) = v m/sFinal velocity (v) = -3v m/sUsing Newton's third equation of motion :v² - u² =2as(3v)² - v² = 2*(-g)(-h)

Let the height of the tower be h.Initial velocity (u) = v m/sFinal velocity (v) = -3v m/sUsing Newton's third equation of motion :v² - u² =2as(3v)² - v² = 2*(-g)(-h)Hence h = 4v²/g.

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