Question

A ball is thrown vertically upward with the speed of 40m/s . Find vertical height and total time of flight. take acceleration = 10 m/s^2​

Answer 1

Time of flight is t=
g
2u
​
=
10
2×40
​
=8sec
So time taken to reach at maximum height is t
1
​
=t/2=4sec
Maximum vertical height d=ut
1
​
−
2
gt
1
2
​

​

d=40×4−
2
10×4
2

​
=80m
So after time 4 sec displacement is 80 m and also the distance covered is 80m.
After 8 sec it will reach back to ground, so displacement is zero and total distance traveled is 2d=2×80=160m