A ball is thrown vertically upward with the speed of 40m/s . Find vertical height and total time of flight. take acceleration = 10 m/s^2
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Time of flight is t=
g
2u
=
10
2×40
=8sec
So time taken to reach at maximum height is t
1
=t/2=4sec
Maximum vertical height d=ut
1
−
2
gt
1
2
d=40×4−
2
10×4
2
=80m
So after time 4 sec displacement is 80 m and also the distance covered is 80m.
After 8 sec it will reach back to ground, so displacement is zero and total distance traveled is 2d=2×80=160m
g
2u
=
10
2×40
=8sec
So time taken to reach at maximum height is t
1
=t/2=4sec
Maximum vertical height d=ut
1
−
2
gt
1
2
d=40×4−
2
10×4
2
=80m
So after time 4 sec displacement is 80 m and also the distance covered is 80m.
After 8 sec it will reach back to ground, so displacement is zero and total distance traveled is 2d=2×80=160m
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