a ball is thrown vertically upward with the velocity 98m/s.caculate the maximum. height to which it rises and the total time it takes to return the surface of the earth.
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v = u + at
v = o u = 98 a = -g
t = 10s
s = ut -gt^2/2
s = 98*10 - 4.9*100 = 490m
v = o u = 98 a = -g
t = 10s
s = ut -gt^2/2
s = 98*10 - 4.9*100 = 490m
Answered by
28
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