a ball is thrown vertically upward with velocity 20 m/s from the top of the tower height of tower is 25 m from ground find how high ball will rise (b)total time taken to strike the ground (c) what velocity it strike the ground .
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t_max height=v/g=20/9.8=2.04 secs
d=1/2 gt²
=4.9(4.165)
=20.4m above the building
If v_final=30 m/s, then:
v_final=√2gh
(30)²=900=2 x 9.8 x h
=19.6h
h=45.92
45.92–20.4=25.52m as the height of the building
Hope it will help you.....
d=1/2 gt²
=4.9(4.165)
=20.4m above the building
If v_final=30 m/s, then:
v_final=√2gh
(30)²=900=2 x 9.8 x h
=19.6h
h=45.92
45.92–20.4=25.52m as the height of the building
Hope it will help you.....
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