A ball is thrown vertically upward with velocity 30 metre per second if the acceleration due to gravity is 10 metre per second square what will be the distance travelled by it in the last second of upward motion
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t=v-u/a
t=30/10
t=3
s=ut+1/2at^2
s=0+1/2*10*3*3
s=45
t=30/10
t=3
s=ut+1/2at^2
s=0+1/2*10*3*3
s=45
harimohansharma6481:
wrong answer
hii
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