A ball is thrown vertically upward with velocity of 10m/s. calculate the height attained by the ball and the time taken by it to reach the highest point if the acceleration of the ball is -10m/s^2 during its motion.
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Answers
Answer:
gravity, also called gravitation, in mechanics, the universal force of attraction acting between all matter. ... On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them. Gravity is measured by the acceleration that it gives to freely falling objects.
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Answer:
Correct option is
Correct option isC
Correct option isC2(g2T2+8gH)
Correct option isC2(g2T2+8gH)Let the velocity of ball near roof top be 'v'
Correct option isC2(g2T2+8gH)Let the velocity of ball near roof top be 'v'By kinematics equations,
Correct option isC2(g2T2+8gH)Let the velocity of ball near roof top be 'v'By kinematics equations,v=u+at
Correct option isC2(g2T2+8gH)Let the velocity of ball near roof top be 'v'By kinematics equations,v=u+at0=v′−gT/2
Correct option isC2(g2T2+8gH)Let the velocity of ball near roof top be 'v'By kinematics equations,v=u+at0=v′−gT/2v′=2gT
Correct option isC2(g2T2+8gH)Let the velocity of ball near roof top be 'v'By kinematics equations,v=u+at0=v′−gT/2v′=2gTBy applying v2=u2−2gH
Correct option isC2(g2T2+8gH)Let the velocity of ball near roof top be 'v'By kinematics equations,v=u+at0=v′−gT/2v′=2gTBy applying v2=u2−2gH4g2T2=u2−2gH
Correct option isC2(g2T2+8gH)Let the velocity of ball near roof top be 'v'By kinematics equations,v=u+at0=v′−gT/2v′=2gTBy applying v2=u2−2gH4g2T2=u2−2gHu=2g2T2+8Hg