Question

a ball is thrown vertically upward with velocity of 98 how long does the ball remain in the air​

Answer 1

Answer:

helps if you think of g as 9.8 m/s per second and realise at that rate 98 m/s will be gone in 10 seconds. The average upward velocity is 49 m/s so it rises 490 metres.

Answer 2

Explanation:

u=98mps

v=0

g=-10 ms2

so v=u+gt

0=98-10t

9.8=t

v^2=u^2+2as

0^2=98^2+2*-10*s

-196=-20s

s=9.8m

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