Question

a ball is thrown vertically upward with velocity of 98m/s .calculate the maximum height to which it rises and time taken to return to the surface of Earth?
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Answer 1

Answer:

maximum height= 490 m, time=10 sec

Explanation:

let ball thrown with initial velocity u m/sec

at maximum height final velocity become zero i.e v=0

therefore,

using equation

v^2-u^2=2as      (take a= -9.8m/sec)

0-(98)^2= 2*(-9.8)*s

solving equation we get maximum height

s= 490 m

time taken to return earth

v=u+at

0=98-9.8t

solving equation

t=10sec