Question

a ball is thrown vertically upwards and reaches a max height in 3 sec find the velocity with which it was thrown upwards , and the maxi height attained by the ball

Answer 1

time to reach max height =

$u \div g$

3 = u÷10

u=30 m/s

Max height =

${u}^{2} \div 2g$

Max height = 900/20 = 45m

Hope this helps ...