Question

A ball is thrown vertically upwards and reaches a maximum height in 3 sec. Find (i) the velocity with which it has thrown upwards.
(ii) The maximum height attained by the ball. (g= 10m/sec2)

Answer 1

Answer:

u=?      v=0

g= -10m/s  t=3

1. )v= u +gt

0=u+(-10*3)

0=u+(-30)

u=+ 30m/s

2) APPLY  h=ut +1/2*gt^2

h=30*3-1/2*10*9

h=90-45=45

Answer 2

Answer:

u=? t=3s

v=0. g=-10/s²

v=u+gt

0=u+(-10)3

o=u+(-30)

u=+30m/s

apply h=ut+1÷2 ×gt²

h=30×3-1÷2×10×9

h=90-45=45