Question

A ball is thrown vertically upwards and reaches a maximum height in 3s. The velocity with which it was thrown upwards is (Take g= 10 metre per second square )​

Answer 1

Answer:

30m/s

Explanation:

At max ht. v=0

u=u

a=-g

v^2-u^2=2aS

0^2-u^2=2*-g*S

S=u^2/2g S is the max ht.

Now t=3

a=-g

u=u

S=ut+1/2at^2

u^2/2g=u(3)-1/2*g*(3)^2

u^2/2g=3u-9g/2

By solving this you get

u=30m/s

Mark me as brainliest if you wish

Hope it helps