a ball is thrown vertically upwards and reaches the height of 20m and comes back . calculate initial velocity and the time which the object was in air?...
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Explanation:
A) The initial velocity of the ball is 20m/s :
As it reaches a maximum height of 20m
and the acceleration is 10m/s^2.
So in order to reach a height of 20m ,with an acc. in opp. direction it has to move with 20m/s
b) 20m/s
As the velocity of any object thrown upward with some speed lands on the ground with the sane speed
c) use v=u+at
0=20-10t
»t=2 sec
but this is the time it reach the max. height
so it will take 2 more sec to reach ground
» Time = 4 sec
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