A ball is thrown vertically upwards and return to the thrown after 12sec(g=9.8).find the velocity with it was thrown up
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Total time taken = 12 sec, g=9.8 m/s^2, v=0
Time taken to reach the maximum height =12/2 = 6 sec
using (i) equation of motion
v=u+at
0=u+(-9.8)6 (NEGATIVE SIGN IS DUE TO THE UPWARD MOTION)
0=u-58.8
u=58.8
Time taken to reach the maximum height =12/2 = 6 sec
using (i) equation of motion
v=u+at
0=u+(-9.8)6 (NEGATIVE SIGN IS DUE TO THE UPWARD MOTION)
0=u-58.8
u=58.8
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@sunita
Please see the attached picture..
HOPE IT HELPS YOU..
REGARDS
@sunita
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