Question

A ball is thrown vertically upwards and rises to a height of 126.5 m. Calculate the velocity by which the ball was thrown upwards and the time taken by the ball to reach the highest point.

Answer 1

Answer:

The velocity is 250m/s

Time taken is 25sec

Explanation:

Given data,

Height (H)=126•5m

Velocity (v)=required

Time (t)=required

From, the formula

V = gt but, we don't have t

Again from,

H=1gt²/2 but,H=126•5m and g=10N/kg

126•5=1×10×t²/2

126•5×2=10t²

253=10t² you by 10 both sides

It will be 25•3=to

If you approximate 25•3 it will be exactly 25 so

25=t²

√25=√t²

t=25sec

Again from,

v=gt

v=10×25

V=250m/s

Hope it's helpful

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Answer 2

Answer:

Hi...

I hope this will help u..

H=u²/2g

80 =u²/2g

u = 40 m/s

Time of ascent = u/g

= 40/10

=4s

Explanation: