Question

A ball is thrown vertically upwards and rises to a height of 10 m. The velocity with which the

object was thrown upwards is​

Answer 1

Step-by-step explanation:

Maximum height  h=10 m/s

At maximum height,   v=0

Let the initial velocity be u.

Acceleration   a=−g=−9.8 m/s2

∴  0−u2=2(−9.8)(h)

⟹ u=2gh

​=2×9.8×10

​=14 m/s

hope it helps

Answer 2

Given:-

v(final velocity) = 0 (since it's thrown upward)

a (acceleration due to gravity) = 10 m/s² [it will be taken negative in the equation]

s(height) = 10m

To Find:-

u(initial velocity) = ?

Solution:-

As we know,

$\implies$v² - u² = 2as

$\implies$(0)² - u² = 2×(-10)×10

$\implies$- u² = -200

$\implies$u = $\sqrt{200}$

$\implies$u = 10$\sqrt{2}$ m/s ...ans....