Question

A ball is thrown vertically upwards at 25m/s. Gravity causes the ball to decelerate at 10 m/s^2. Calculate the maximum height the ball will reach. Please use the formula v^2=u^2+2as

Answer 1

Okay using This Formulaic

v = final velocity

u = 25

g = -10m/s^2 = a because ball thrown upward

v^2 = u ^ 2 + 2 g s

0 = 625 + 2 * -10 * s

0 = 625 + -20 * s

-625 / -20= s

31.25 = s

Height = 31.25 m

Answer 2

Answer:31.25 meters

Explanation:

In this question:

u = 0 m/s

v = 25 m/s

a = 10 m/s^2

s = ?

Rearrange the equation:

v^2=u^2+2as to make "s" the subject:

s = (v^2-u^2)/2a

Now put in the values:

s = (25^2-0^2)/(2*10)

s = 31.25 m/s