A ball is thrown vertically upwards at an initial speed of 23m.s-1. What is the distance travelled by the ball 3 seconds after it was thrown?
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Answer:
s = ut + 1 /2 gt^2
= 23 m/s * 3 s + 1/2*10*3^2
= 69 + 45
= 114 m
the distance travelled by the ball is equal to 114 m .
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