Physics, asked by fatimarosebiadnes, 9 months ago

A ball is thrown vertically upwards at an initial speed of 23m.s-1. What is the distance travelled by the ball 3 seconds after it was thrown?

Answers

Answered by Anonymous

0

Answer:

s = ut + 1 /2 gt^2

= 23 m/s * 3 s + 1/2*10*3^2

= 69 + 45

= 114 m

the distance travelled by the ball is equal to 114 m .

hope it helps you

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