Question

A ball is thrown vertically upwards at the speed of 49m\s. Calculate.
1.maxixmum height of the ball
2.total time taken by the ball to reach the earth's surface ​

Answer 1

Answer:

i) 122.5 m

ii) 10s

Explanation:

Given Initial velocity of ball, u=49 m/s

Let the maximum height reached and time taken to reach that height be H and t respectively.

Assumption: g=9.8 m/s² holds true (maximum height reached is small compared to the radius of earth)

Velocity of the ball at maximum height is zero, v=0

v²-u² =2aH                          

0−(49)² =2×(−9.8)×H          

⟹H=122.5 m                

v=u + at

0=49−9.8t            

⟹t=5 s

∴ Total time taken by ball to return to the surface, T=2t=10 s

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