A ball is thrown vertically upwards from the top of a tower with a velocity of 20m/s.The ball strikes the earth after 5s of its throwing.What is the height of the tower ? What will be the velocity of the ball while striking the earth?
PLEASE DO IT ASAP AND EXPLAIN IT IN AS MUCH DETAIL AS POSSIBLE
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Answer:
u( initial velocity)=20 m/s
time=5sec
acceleration due to gravity =9.8n
s(height)=?
s=ut +1/2at^
s=
Explanation:
S is equal to UT plus half a t square
because we have given initial velocity and time so we will calculate the height first and then will calculate the final velocity when it reaches ground
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