Physics, asked by abhaysingh060902, 10 months ago

A ball is thrown vertically upwards from the top of a tower with a velocity of 20m/s.The ball strikes the earth after 5s of its throwing.What is the height of the tower ? What will be the velocity of the ball while striking the earth?
PLEASE DO IT ASAP AND EXPLAIN IT IN AS MUCH DETAIL AS POSSIBLE

Answers

Answered by kashvis
0

Answer:

u( initial velocity)=20 m/s

time=5sec

acceleration due to gravity =9.8n

s(height)=?

s=ut +1/2at^

s=

Explanation:

S is equal to UT plus half a t square

because we have given initial velocity and time so we will calculate the height first and then will calculate the final velocity when it reaches ground

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