a ball is thrown vertically upwards from the top of a tower with a speed of 100m/s. it strilces the point near the base of the tower after 25sce.find the height of the tower.
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Answer:
750m
Explanation:
Case-1
a ball is thrown vertically upwards from top of a tower with a speed of 100m/s
Then calculate Time of acent for it
Ta = u/g
Ta = 100/10
Ta = 10sec
so Time of decent is also same as Time of acent .
Total time of flight to reach same level of top of the floor is 20sec
Then time taken by the ball to reach the ground from top of the tower is
t= 25 - 20
= 5 sec
that means ball travels to the base of the tower in 5 sec with speed 100 m/s
use formula
. S=ut + 1/2 at^2
= 100*5 + 10*5^2
= 500 + 250
= 750 m
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