A ball is thrown vertically upwards from the top of a tower with an initial velocity of 19.6 m/s. The ball reaches the ground after 5 seconds. Calculate : (I) the height of the tower, (ii) the velocity of the ball on reaching the ground. Take g=9.8m/s^2.
Plz answer with all the steps in detail... If the answer is proper I will mark it as the brainliest answer.....
Answers
Answered by
1
hii
here is your answer
u=19.6m/s
t=5sec
a=9.8
s=u+1/2at^
19.6+1/2×9.8×5×5
19.6+4.6×25
115 + 19.6
134.6
hope it helps
here is your answer
u=19.6m/s
t=5sec
a=9.8
s=u+1/2at^
19.6+1/2×9.8×5×5
19.6+4.6×25
115 + 19.6
134.6
hope it helps
agarwalkushang:
Your answer is totally wrong and moreover u have answered only the half of the question
why
I also asked the velocity and the height is 24.5 grams
Sry 24.5 metres
Anyway thanks for trying
Answered by
1
hope it helps. .....
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Bro sry to say but it is wrong
I don’t know why but that isn’t the answer
oo really
i dont think so
coz i have cross checked it
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