A ball is thrown vertically upwards from the top
of a tower with a velocity of 10 m/sec. if the ball falls on the ground after 5 sec what height above the
tower will the ball attain?
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Explanation:
ANSWER
We know that,
s=+ut+
2
1
at
2
s=+(10)(5)+
2
1
(10)(5)
2
s=+50+
2
1
×10×25
s=50+50m=100m
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