a ball is thrown vertically upwards from the top of the tower with the velocity of 20 m/s.The ball strikes the earth after 5s of its throwing.what is the height of the tower?and the velocity of ball while striking the ground?
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u=20m/s
t=5s
a=9.8
s=ut+1/2at²
s=20×5+1/2×9.8×5×5
s=222.5m
v=u+at
v=20+9.8×5
v=69
so distance is 222.5 and final velocity is 69m/s
hope that help you....
t=5s
a=9.8
s=ut+1/2at²
s=20×5+1/2×9.8×5×5
s=222.5m
v=u+at
v=20+9.8×5
v=69
so distance is 222.5 and final velocity is 69m/s
hope that help you....
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