a ball is thrown vertically upwards from the top of tower with a velocity of 20m/s.the ball strikes the earth after 5s of its throwing.What is the height of the tower.What will be the velocity of the ball while striking the earth?
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T = 2u / g
= 2 * 20 / 10
= 4 seconds
t = 5 - T
= 5 - 4
= 1
H = ut + 0.5gt^2
= (20 * 1) + (0.5 * 10 * 1^2)
= 25 m
v = sqrt(u^2 + 2gH)
= sqrt(20^2 + (2 * 10 * 25))
= 30 m/s
Height of the tower = 25 m
Velocity when the ball strkes the earth = 30 m/s
= 2 * 20 / 10
= 4 seconds
t = 5 - T
= 5 - 4
= 1
H = ut + 0.5gt^2
= (20 * 1) + (0.5 * 10 * 1^2)
= 25 m
v = sqrt(u^2 + 2gH)
= sqrt(20^2 + (2 * 10 * 25))
= 30 m/s
Height of the tower = 25 m
Velocity when the ball strkes the earth = 30 m/s
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