Question

A ball is thrown vertically upwards from the top of tower with a speed of 100m/s it strikes the pond near the base of the tower after 25 sec . the height of tower is

Answer 1

Hello mate !!

Answer is in attachment.

Hope this helps !!

Answer 2

Answer:

The height of the tower is 562.5 m

Explanation:

Given that,

Speed u= 100 m/s

Time t = 25 sec

Using equation of motion

$S_{y}=u_{y}t-\dfrac{1}{2}gt^2+h_{0}$.....(I)

Where, u = velocity

t = time

g = acceleration due to gravity

h = height of tower

Put the value in the equation (I)

$0=100\times25-\dfrac{1}{2}\times9.8\times25^2+h_{0}$

$h_{0}=562.5\ m$

Hence, The height of the tower is 562.5 m