Question

A ball is thrown vertically upwards it goes to a height of 19.6 m and then returns back to the ground find the initial velocity of the ball the total time taken to the germany final velocity of the wall when is playground gravitation is equals to 9.8 metre per square

Answer 1

We will use the following equation of motion


V² = U² - 2gs

Since it is projected upwards :

V = 0

0 = u² - 384.16

U² = 384.16

U = 19.6 m / s

Time taken to reach highest point is :

S = ut - 0.5gt²

19.6 = 19.6 t - 4.9t²

4.9t² - 19.6 t + 19.6 = 0

t = {19.6 +/- √384.16 - 384.16} /9.8

= 2 seconds

Time taken to go up and come down:

2 × 2 = 4 seconds.

Answer 2

Answer:

Explanation:

We will use the following equation of motion

V² = U² - 2gs

Since it is projected upwards :

V = 0

0 = u² - 384.16

U² = 384.16

U = 19.6 m / s

Time taken to reach highest point is :

S = ut - 0.5gt²

19.6 = 19.6 t - 4.9t²

4.9t² - 19.6 t + 19.6 = 0

t = {19.6 +/- √384.16 - 384.16} /9.8

= 2 seconds

Time taken to go up and come down:

2 × 2 = 4 seconds.