Question

a ball is thrown vertically upwards.It goes to height 19.6m.Find initial velocity of the ball.the total time of journey​

Answer 1

Answer:

g= -9.8m/sec^2

height= 19.6m

v=0

t=

u=?

using v^=u^2+ 2as

0=u^2- 2 x 9.8 x 19.6

384.16 = u^2

u= 19.6 m/sec

using v=u+ at

0= 19.6 - 9.8 x t

-19.6= -9.8t

t= 19.6/ 9.8

t= 2 second

Explanation:

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