A ball is thrown vertically upwards. It passes a point 50 m high at t1 and t2 while going upwards and coming down
respectively. The value of product t1t2, if g = 10 m/s?, is
10
25
20
50
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Answer:
Since air resistance is not ignored, thus while going up, resistance acts opposite to velocity or in downwards direction. Thus net acceleration is in downwards direction and is equal to a+g, which opposes motion. Thus time taken will reduce to bring it to stop. While coming down, r acts opposite to velocity , i.e. upwards, thus net force or acceleration is downwards =a−g. Since acceleration is lower in this case, time will not decrease that much as compared to a+g. Thus T
1
will be less than T
2
Explanation:
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