A ball is thrown vertically upwards, it reaches a maximum height of 25 metres. What was the initial speed of the ball? How much time is taken by the ball to reach the highest point? *
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2gs = v^2-u^2
2×-9.8×25 = 0^2- u^2
-490 = -u^2
490=u^2
√490 = u
22.13 = u
v= u + gt
0= 22 + -9.8t
-22 =-9.8t
22=9.8t
22/9.8= t
2.24 sec
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