A ball is thrown vertically upwards. It retums
6 s later. Calculate : (i) the greatest height
reached by the ball, and (ii) the initial velocity
of the ball. (Take g = 10 m )
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Answer:
(i.) 45m, (ii.)30m/s
Explanation:
(i.)
Let us consider the ball falling from the highest point to the ground
so
H =1/2gt²
H = 1/2(10m/s)(3²)
H = 45m
3 Because Time of falling and going up = 6, so time of only going up or down = 3
(ii.)
Now let us consider the ball to return from the target to the point of where ball was thrown from
H = ut - 1/2gt²
0 = ut - 1/2(10m/s)(6)²
u = 10 * 6/2 = 30m/s
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