Question

A ball is thrown vertically upwards. It returns
6 s later. Calculate : fit the greatest height reached
by the ball, and if the initial velocity of the ball,
(Take g = 10 m s^)

Answer 1

time taken for maximum height=6/2=3s

we know

v=u+at

0=u+ (-10)3

u=30m/s

and

$s = ut + 1 \div 2at {}^{2} \\ \: \: = \: 30 \times 3 + 1 \div 2 \times 10 \times 3 \\ \: \: \: = 105m$

I hope it is helpful for u