Question

A ball is thrown vertically upwards.It returns 6 sec later.calculate the greatest height reached by the ball

Answer 1

hii
here is your answer
t =3sec
a=-9.8
v=0
v=u+at
=u+-9.8×3
u=29.4

s=ut+1/2at^2
29.4×3+1/2×-9.8×3×3

=-44.1
the maximum distance reached is -44.1
hope it helps